Showing posts with label CS302. Show all posts
Showing posts with label CS302. Show all posts

Monday, November 8, 2010

CS302 Assignment # 1 Solution

Question_1:

Convert following decimal values to binary:

3.25
3.25 = 11.01
20.20
10100.00110011

Question_2:
Express each decimal number as an 8-bit number in the 2's complement form:

+18
00010010
-117
11110101

Question_3:
Represent the following binary numbers in Hexadecimal:

1111110000
0011
1111
0000 3
F
0
Two zeros have been added to complete a 4-bit ***** at the left
1001001001000
0001
0010
0100
1000 1

2
4
8
Three zeros have been added to complete a 4-bit ***** at the left
Question_4:
What is the highest decimal number that can be represented by each of the following numbers of binary digits (bits) ? (litlle doubted plz confirm ur self)

two
10
eight
1000
sixteen
10000
thirty-two
100000

Thursday, February 4, 2010

CS302 GDB

CS302 GDB Solution…..
When we convert continues signal in to digital
we can get the exact information. No chance of
lost of information because digital system have
only two values. While in analogue signal much
distortion is there.
Analogue to digital conversion is easy. Because
in this conversion we just break the signals in to
parts then quantized that assign values.
But in digital to analogue conversion is very
difficult there are so many processes. Like
ASK, FSK, PSK and QSK. It becomes very
difficult to choose exact method of conversion.
And these methods of conversion are difficult to
implement.